x=4x^2-5x+3

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Solution for x=4x^2-5x+3 equation: 



x=4x^2-5x+3

We move all terms to the left:

x-(4x^2-5x+3)=0

We get rid of parentheses

-4x^2+x+5x-3=0

We add all the numbers together, and all the variables

-4x^2+6x-3=0

a = -4; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·(-4)·(-3)
Δ = -12
Delta is less than zero, so there is no solution for the equation

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